What is factor 2x^4-7x^3+3x^2+8x-4 ?

The solution to factor 2x^4-7x^3+3x^2+8x-4 is (x+1)(2x-1)(x-2)^2

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factor 2x^4-7x^3+3x^2+8x-4

factor

2 x^{4} - 7 x^{3} + 3 x^{2} + 8 x - 4

(x + 1) (2 x - 1) (x - 2)^{2}

Solution steps

2 x^{4} - 7 x^{3} + 3 x^{2} + 8 x - 4

Use the rational root theorem

= (x + 1) \frac{2 x ^{4} - 7 x ^{3} + 3 x ^{2} + 8 x - 4}{x + 1}

\frac{2 x ^{4} - 7 x ^{3} + 3 x ^{2} + 8 x - 4}{x + 1} = 2 x^{3} - 9 x^{2} + 12 x - 4

= (x + 1) (2 x^{3} - 9 x^{2} + 12 x - 4)

Factor

2 x^{3} - 9 x^{2} + 12 x - 4 : (2 x - 1) (x - 2) (x - 2)

= (x + 1) (2 x - 1) (x - 2) (x - 2)

Apply exponent rule:

aa = a^{2}

(x - 2) (x - 2) = (x - 2)^{2}

= (x + 1) (2 x - 1) (x - 2)^{2}

3 X^{2} = - 99

(9 x)^{2}

4 a^{2} - 25

c^{2} - 16

5.4 y^{2} - 10.8 y = 0

What is factor 2x^4-7x^3+3x^2+8x-4 ?
The solution to factor 2x^4-7x^3+3x^2+8x-4 is (x+1)(2x-1)(x-2)^2