What are the solutions to the equation x^2+22=10x ?

The solutions to the equation x^2+22=10x are x=5+sqrt(3),x=5-sqrt(3)

Find the zeros of x^2+22=10x

The zeros of x^2+22=10x are x=5+sqrt(3),x=5-sqrt(3)

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x^{2} + 22 = 10 x

x = 5 + 3, x = 5 - 3

Solution steps

x^{2} + 22 = 10 x

Move

10 x

to the left side

x^{2} + 22 - 10 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 10 x + 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 22}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 22 = 23

x_{1, 2} = \frac{- ( - 10 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 3}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 3}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 3}{2 \cdot 1} : 5 + 3

x = \frac{- ( - 10 ) - 2 3}{2 \cdot 1} : 5 - 3

The solutions to the quadratic equation are:

x = 5 + 3, x = 5 - 3

5 x - 4 < 2 x + 5

\frac{49}{81}

x^{2} + 9 - 25

- 2 x - 3 = 15

(v - 7)^{2} - 20 = 0

What are the solutions to the equation x^2+22=10x ?
The solutions to the equation x^2+22=10x are x=5+sqrt(3),x=5-sqrt(3)
Find the zeros of x^2+22=10x
The zeros of x^2+22=10x are x=5+sqrt(3),x=5-sqrt(3)