What are the solutions to the equation 4x^2-x+3=0 ?

The solutions to the equation 4x^2-x+3=0 are x= 1/8+i(sqrt(47))/8 ,x= 1/8-i(sqrt(47))/8

Find the zeros of 4x^2-x+3=0

The zeros of 4x^2-x+3=0 are x= 1/8+i(sqrt(47))/8 ,x= 1/8-i(sqrt(47))/8

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4 x^{2} - x + 3 = 0

x = \frac{1}{8} + i \frac{47}{8}, x = \frac{1}{8} - i \frac{47}{8}

Solution steps

4 x^{2} - x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

Simplify

(- 1)^{2} - 4 \cdot 4 \cdot 3 : 47 i

x_{1, 2} = \frac{- ( - 1 ) \pm 47 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 47 i}{2 \cdot 4}, x_{2} = \frac{- ( - 1 ) - 47 i}{2 \cdot 4}

x = \frac{- ( - 1 ) + 47 i}{2 \cdot 4} : \frac{1}{8} + i \frac{47}{8}

x = \frac{- ( - 1 ) - 47 i}{2 \cdot 4} : \frac{1}{8} - i \frac{47}{8}

The solutions to the quadratic equation are:

x = \frac{1}{8} + i \frac{47}{8}, x = \frac{1}{8} - i \frac{47}{8}

9 k^{2} - 30 k + 25

3 (x + 5) = 2 (- 6 - x) - 2 x

\frac{n ( n + 1 )}{2} + n + 1

- \frac{24}{- 6}

x^{2} - 4 x - 17 = 4

What are the solutions to the equation 4x^2-x+3=0 ?
The solutions to the equation 4x^2-x+3=0 are x= 1/8+i(sqrt(47))/8 ,x= 1/8-i(sqrt(47))/8
Find the zeros of 4x^2-x+3=0
The zeros of 4x^2-x+3=0 are x= 1/8+i(sqrt(47))/8 ,x= 1/8-i(sqrt(47))/8