What is (2x^{-2}y^4z^{-5})^3 ?

The solution to (2x^{-2}y^4z^{-5})^3 is (8y^{12})/(x^6z^{15)}

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simplify (2x^{-2}y^4z^{-5})^3

simplify

(2 x^{- 2} y^{4} z^{- 5})^{3}

\frac{8 y ^{12}}{x ^{6} z ^{15}}

Solution steps

(2 x^{- 2} y^{4} z^{- 5})^{3}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(2 x^{- 2} y^{4} z^{- 5})^{3} = 2^{3} (x^{- 2})^{3} (y^{4})^{3} (z^{- 5})^{3}

= 2^{3} (x^{- 2})^{3} (y^{4})^{3} (z^{- 5})^{3}

2^{3} = 8

= 8 (x^{- 2})^{3} (y^{4})^{3} (z^{- 5})^{3}

Simplify

(x^{- 2})^{3} : \frac{1}{x ^{6}}

= 8 \cdot \frac{1}{x ^{6}} (y^{4})^{3} (z^{- 5})^{3}

Simplify

(y^{4})^{3} : y^{12}

= 8 \cdot \frac{1}{x ^{6}} y^{12} (z^{- 5})^{3}

Simplify

(z^{- 5})^{3} : \frac{1}{z ^{15}}

= 8 \cdot \frac{1}{x ^{6}} y^{12} \frac{1}{z ^{15}}

Simplify

8 \cdot \frac{1}{x ^{6}} y^{12} \frac{1}{z ^{15}} : \frac{8 y ^{12}}{x ^{6} z ^{15}}

= \frac{8 y ^{12}}{x ^{6} z ^{15}}

\frac{4}{5} - \frac{3}{8}

x^{2} \cdot 3 x

5280 (1 + \frac{0.042}{12})^{12 (8)}

\frac{x ^{3}}{x ^{6}}

lo g_{\frac{1}{5}} (6)

What is (2x^{-2}y^4z^{-5})^3 ?
The solution to (2x^{-2}y^4z^{-5})^3 is (8y^{12})/(x^6z^{15)}