What is the answer to 2(2+x)-(6-7x)=133x-(1+4x) ?

The answer to 2(2+x)-(6-7x)=133x-(1+4x) is x=-1/120

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2(2+x)-(6-7x)=133x-(1+4x)

2 (2 + x) - (6 - 7 x) = 133 x - (1 + 4 x)

x = - \frac{1}{120}

Decimal Notation

x = - 0.00833 \dots

Solution steps

2 (2 + x) - (6 - 7 x) = 133 x - (1 + 4 x)

Expand

2 (2 + x) - (6 - 7 x) : 9 x - 2

Expand

133 x - (1 + 4 x) : 129 x - 1

9 x - 2 = 129 x - 1

Move

2

to the right side

9 x = 129 x + 1

Move

129 x

to the left side

- 120 x = 1

Divide both sides by

- 120

x = - \frac{1}{120}

3^{e} = x

(\frac{- 7 a ^{2} b ^{3} c ^{0}}{3 a ^{3} b ^{4} c ^{3}})^{- 4}

(x + 3) (x - 2) \leq 0

2 x^{2} + 18 = 0

∣ x - 1 ∣ > 3

What is the answer to 2(2+x)-(6-7x)=133x-(1+4x) ?
The answer to 2(2+x)-(6-7x)=133x-(1+4x) is x=-1/120
Solve for x: 2(2+x)-(6-7x)=133x-(1+4x)
The solution is x=-1/120