What is factor x^4+3x^3-2x^2-12x-8 ?

The solution to factor x^4+3x^3-2x^2-12x-8 is (x+1)(x+2)^2(x-2)

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factor x^4+3x^3-2x^2-12x-8

factor

x^{4} + 3 x^{3} - 2 x^{2} - 12 x - 8

(x + 1) (x + 2)^{2} (x - 2)

Solution steps

x^{4} + 3 x^{3} - 2 x^{2} - 12 x - 8

Use the rational root theorem

= (x + 1) \frac{x ^{4} + 3 x ^{3} - 2 x ^{2} - 12 x - 8}{x + 1}

\frac{x ^{4} + 3 x ^{3} - 2 x ^{2} - 12 x - 8}{x + 1} = x^{3} + 2 x^{2} - 4 x - 8

= (x + 1) (x^{3} + 2 x^{2} - 4 x - 8)

Factor

x^{3} + 2 x^{2} - 4 x - 8 : (x + 2) (x + 2) (x - 2)

= (x + 1) (x + 2) (x + 2) (x - 2)

Apply exponent rule:

aa = a^{2}

(x + 2) (x + 2) = (x + 2)^{2}

= (x + 1) (x + 2)^{2} (x - 2)

(q - 1)^{2} = 0.75

∣ x ∣ \leq 25

3 (x + 1) + 4 = 2 (x - 1) + x

x^{2} - 4 x - 32

- 7 \cdot 6

What is factor x^4+3x^3-2x^2-12x-8 ?
The solution to factor x^4+3x^3-2x^2-12x-8 is (x+1)(x+2)^2(x-2)