What is the d/(dq)(q+r+s) ?

The d/(dq)(q+r+s) is (dr)/(dq)+1

What is the first d/(dq)(q+r+s) ?

The first d/(dq)(q+r+s) is (dr)/(dq)+1

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\frac{d}{d q} (q + r + s)

\frac{d r}{d q} + 1

Solution steps

\frac{d}{d q} (q + r + s)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d q}{d q} + \frac{d r}{d q} + \frac{d s}{d q}

\frac{d q}{d q} = 1

\frac{d s}{d q} = 0

= 1 + \frac{d r}{d q} + 0

Simplify

= \frac{d r}{d q} + 1

2 x - 17 \geq - 27

A^{2} - B^{2}

- 2 b k^{2} + 6 bk - 2 b

\frac{45}{2}

36 x^{2} + 24 x