What are the solutions to the equation 0=x^2-4x+4 ?

The solutions to the equation 0=x^2-4x+4 are x=2

Find the zeros of 0=x^2-4x+4

The zeros of 0=x^2-4x+4 are x=2

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0 = x^{2} - 4 x + 4

x = 2

Solution steps

0 = x^{2} - 4 x + 4

Switch sides

x^{2} - 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 4 )}{2 \cdot 1}

\frac{- ( - 4 )}{2 \cdot 1} = 2

x = 2

The solution to the quadratic equation is:

x = 2

\frac{1}{2} 5 (5 - 3)

x^{2} + 9 x = - 14

x^{3} - 4 x^{2} + 4 x - 16

14 y = 7 y + 14

3 (2 x - 4) + \frac{5 x + 1}{6} = \frac{1}{4}

What are the solutions to the equation 0=x^2-4x+4 ?
The solutions to the equation 0=x^2-4x+4 are x=2
Find the zeros of 0=x^2-4x+4
The zeros of 0=x^2-4x+4 are x=2