What is (a^{2/3}b^{-1/2})^{-6} ?

The solution to (a^{2/3}b^{-1/2})^{-6} is (b^3)/(a^4)

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simplify (a^{2/3}b^{-1/2})^{-6}

simplify

(a^{\frac{2}{3}} b^{- \frac{1}{2}})^{- 6}

\frac{b ^{3}}{a ^{4}}

Solution steps

(a^{\frac{2}{3}} b^{- \frac{1}{2}})^{- 6}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(a^{\frac{2}{3}} b^{- \frac{1}{2}})^{- 6} = \frac{1}{( a ^{\frac{2}{3}} b ^{- \frac{1}{2}} ) ^{6}}

= \frac{1}{( a ^{\frac{2}{3}} b ^{- \frac{1}{2}} ) ^{6}}

Simplify

(a^{\frac{2}{3}} b^{- \frac{1}{2}})^{6} : \frac{a ^{4}}{b ^{3}}

= \frac{1}{\frac{a ^{4}}{b ^{3}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{b ^{3}}{a ^{4}}

5 - 2 (1 - x) = 2 x - 3

\frac{( 1 + i ) ( 1 - i ) ^{- 8}}{( - 9 + 3 i 3 ) ^{- 2}}

∣ x - 1 ∣ - 4 \leq 5

0 \leq x + 2 (4 x - 1) \leq 6

20 + 17 x = - 6 + 15 x

What is (a^{2/3}b^{-1/2})^{-6} ?
The solution to (a^{2/3}b^{-1/2})^{-6} is (b^3)/(a^4)