What are the solutions to the equation p^2+8p+10=0 ?

The solutions to the equation p^2+8p+10=0 are p=-4+sqrt(6),p=-4-sqrt(6)

Find the zeros of p^2+8p+10=0

The zeros of p^2+8p+10=0 are p=-4+sqrt(6),p=-4-sqrt(6)

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p^{2} + 8 p + 10 = 0

p = - 4 + 6, p = - 4 - 6

Decimal Notation

p = - 1.55051 \dots, p = - 6.44948 \dots

Solution steps

p^{2} + 8 p + 10 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 10 = 26

p_{1, 2} = \frac{- 8 \pm 2 6}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 8 + 2 6}{2 \cdot 1}, p_{2} = \frac{- 8 - 2 6}{2 \cdot 1}

p = \frac{- 8 + 2 6}{2 \cdot 1} : - 4 + 6

p = \frac{- 8 - 2 6}{2 \cdot 1} : - 4 - 6

The solutions to the quadratic equation are:

p = - 4 + 6, p = - 4 - 6

\frac{1}{3} x = 3

x^{2} y^{4} - x^{5} y^{2}

16 x^{2} + 56 x y + 49 y^{2}

5 (x - 3) = 1 - (x + 4)

q^{3} - 81 q^{7}

What are the solutions to the equation p^2+8p+10=0 ?
The solutions to the equation p^2+8p+10=0 are p=-4+sqrt(6),p=-4-sqrt(6)
Find the zeros of p^2+8p+10=0
The zeros of p^2+8p+10=0 are p=-4+sqrt(6),p=-4-sqrt(6)