What is factor a^6-b^4 ?

The solution to factor a^6-b^4 is (a^3+b^2)(a^3-b^2)

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factor a^6-b^4

factor

a^{6} - b^{4}

(a^{3} + b^{2}) (a^{3} - b^{2})

Solution steps

a^{6} - b^{4}

a^{6} = (a^{3})^{2}

b^{4} = (b^{2})^{2}

= (a^{3})^{2} - (b^{2})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(a^{3})^{2} - (b^{2})^{2} = (a^{3} + b^{2}) (a^{3} - b^{2})

= (a^{3} + b^{2}) (a^{3} - b^{2})

x^{3} y^{3} - z^{9}

4 x + 9 = 13

(x + 8) + 15 = 2 (x + 15)

(\frac{x ^{- 1} y ^{2}}{x ^{3} y ^{4}})^{- 3}

5 x - 5 < 5 (x - 2)