What are the solutions to the equation 3x^2-10x-2=0 ?

The solutions to the equation 3x^2-10x-2=0 are x=(5+sqrt(31))/3 ,x=(5-sqrt(31))/3

Find the zeros of 3x^2-10x-2=0

The zeros of 3x^2-10x-2=0 are x=(5+sqrt(31))/3 ,x=(5-sqrt(31))/3

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3 x^{2} - 10 x - 2 = 0

x = \frac{5 + 31}{3}, x = \frac{5 - 31}{3}

Decimal Notation

x = 3.52258 \dots, x = - 0.18925 \dots

Solution steps

3 x^{2} - 10 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

(- 10)^{2} - 4 \cdot 3 (- 2) = 231

x_{1, 2} = \frac{- ( - 10 ) \pm 2 31}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 31}{2 \cdot 3}, x_{2} = \frac{- ( - 10 ) - 2 31}{2 \cdot 3}

x = \frac{- ( - 10 ) + 2 31}{2 \cdot 3} : \frac{5 + 31}{3}

x = \frac{- ( - 10 ) - 2 31}{2 \cdot 3} : \frac{5 - 31}{3}

The solutions to the quadratic equation are:

x = \frac{5 + 31}{3}, x = \frac{5 - 31}{3}

- 6 (- n - 5) = - 3 (- 4 + 4 n)

(x + 1) (x + 2) = - 3 x - 3

(5 k - 2)^{2} = 64

3 w^{2} - 22 w = 16

ln (e^{4}) = x

What are the solutions to the equation 3x^2-10x-2=0 ?
The solutions to the equation 3x^2-10x-2=0 are x=(5+sqrt(31))/3 ,x=(5-sqrt(31))/3
Find the zeros of 3x^2-10x-2=0
The zeros of 3x^2-10x-2=0 are x=(5+sqrt(31))/3 ,x=(5-sqrt(31))/3