What are the solutions to the equation x^2+8x-6=0 ?

The solutions to the equation x^2+8x-6=0 are x=-4+sqrt(22),x=-4-sqrt(22)

Find the zeros of x^2+8x-6=0

The zeros of x^2+8x-6=0 are x=-4+sqrt(22),x=-4-sqrt(22)

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x^{2} + 8 x - 6 = 0

x = - 4 + 22, x = - 4 - 22

Decimal Notation

x = 0.69041 \dots, x = - 8.69041 \dots

Solution steps

x^{2} + 8 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 6) = 222

x_{1, 2} = \frac{- 8 \pm 2 22}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 22}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 22}{2 \cdot 1}

x = \frac{- 8 + 2 22}{2 \cdot 1} : - 4 + 22

x = \frac{- 8 - 2 22}{2 \cdot 1} : - 4 - 22

The solutions to the quadratic equation are:

x = - 4 + 22, x = - 4 - 22

X^{3} - 1

1000 = - \frac{x}{- 0.00175}

5 = - 3 + y

4 x^{3} - 10 x^{2} - 50 x

p^{2} - 9 p + 8

What are the solutions to the equation x^2+8x-6=0 ?
The solutions to the equation x^2+8x-6=0 are x=-4+sqrt(22),x=-4-sqrt(22)
Find the zeros of x^2+8x-6=0
The zeros of x^2+8x-6=0 are x=-4+sqrt(22),x=-4-sqrt(22)