What are the solutions to the equation -3x^2+9x-6=0 ?

The solutions to the equation -3x^2+9x-6=0 are x=1,x=2

Find the zeros of -3x^2+9x-6=0

The zeros of -3x^2+9x-6=0 are x=1,x=2

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- 3 x^{2} + 9 x - 6 = 0

x = 1, x = 2

Solution steps

- 3 x^{2} + 9 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 3 ) ( - 6 )}{2 ( - 3 )}

9^{2} - 4 (- 3) (- 6) = 3

x_{1, 2} = \frac{- 9 \pm 3}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 9 + 3}{2 ( - 3 )}, x_{2} = \frac{- 9 - 3}{2 ( - 3 )}

x = \frac{- 9 + 3}{2 ( - 3 )} : 1

x = \frac{- 9 - 3}{2 ( - 3 )} : 2

The solutions to the quadratic equation are:

x = 1, x = 2

9 v^{2} - 64 = 0

\frac{9 + m}{3} = 2

(- 3)^{4}

15 x - 10 y

x^{18} - y^{16}

What are the solutions to the equation -3x^2+9x-6=0 ?
The solutions to the equation -3x^2+9x-6=0 are x=1,x=2
Find the zeros of -3x^2+9x-6=0
The zeros of -3x^2+9x-6=0 are x=1,x=2