What is factor 16b^4-81d^4 ?

The solution to factor 16b^4-81d^4 is (4b^2+9d^2)(2b+3d)(2b-3d)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 16b^4-81d^4

factor

16 b^{4} - 81 d^{4}

(4 b^{2} + 9 d^{2}) (2 b + 3 d) (2 b - 3 d)

Solution steps

16 b^{4} - 81 d^{4}

16 b^{4} = (4 b^{2})^{2}

81 d^{4} = (9 d^{2})^{2}

= (4 b^{2})^{2} - (9 d^{2})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(4 b^{2})^{2} - (9 d^{2})^{2} = (4 b^{2} + 9 d^{2}) (4 b^{2} - 9 d^{2})

= (4 b^{2} + 9 d^{2}) (4 b^{2} - 9 d^{2})

Factor

4 b^{2} - 9 d^{2} : (2 b + 3 d) (2 b - 3 d)

= (4 b^{2} + 9 d^{2}) (2 b + 3 d) (2 b - 3 d)

x^{4} + 3 x^{3} + 4 x^{2} + 3 x + 1

x^{2} - 11 x = - 30

(x - 1) (x - 1)

12 d^{2} + 4 d - 1

(7 x^{2} y^{3}) (3 x^{5} y^{8})

What is factor 16b^4-81d^4 ?
The solution to factor 16b^4-81d^4 is (4b^2+9d^2)(2b+3d)(2b-3d)