What are the solutions to the equation 2x^2-5x=-12 ?

The solutions to the equation 2x^2-5x=-12 are x= 5/4+i(sqrt(71))/4 ,x= 5/4-i(sqrt(71))/4

Find the zeros of 2x^2-5x=-12

The zeros of 2x^2-5x=-12 are x= 5/4+i(sqrt(71))/4 ,x= 5/4-i(sqrt(71))/4

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2 x^{2} - 5 x = - 12

x = \frac{5}{4} + i \frac{71}{4}, x = \frac{5}{4} - i \frac{71}{4}

Solution steps

2 x^{2} - 5 x = - 12

Move

12

to the left side

2 x^{2} - 5 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 \cdot 12}{2 \cdot 2}

Simplify

(- 5)^{2} - 4 \cdot 2 \cdot 12 : 71 i

x_{1, 2} = \frac{- ( - 5 ) \pm 71 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 71 i}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 71 i}{2 \cdot 2}

x = \frac{- ( - 5 ) + 71 i}{2 \cdot 2} : \frac{5}{4} + i \frac{71}{4}

x = \frac{- ( - 5 ) - 71 i}{2 \cdot 2} : \frac{5}{4} - i \frac{71}{4}

The solutions to the quadratic equation are:

x = \frac{5}{4} + i \frac{71}{4}, x = \frac{5}{4} - i \frac{71}{4}

4 x - 9 = 7 x

9 (10 - x) = 63

\frac{4 m}{3 mn} + 2

\frac{n ^{2} - 12 n + 36}{108 - 3 n ^{2}}

3 x^{2} = 1 - 6 x

What are the solutions to the equation 2x^2-5x=-12 ?
The solutions to the equation 2x^2-5x=-12 are x= 5/4+i(sqrt(71))/4 ,x= 5/4-i(sqrt(71))/4
Find the zeros of 2x^2-5x=-12
The zeros of 2x^2-5x=-12 are x= 5/4+i(sqrt(71))/4 ,x= 5/4-i(sqrt(71))/4