What are the solutions to the equation 2(x-3)(x+5)=0 ?

The solutions to the equation 2(x-3)(x+5)=0 are x=3,x=-5

Find the zeros of 2(x-3)(x+5)=0

The zeros of 2(x-3)(x+5)=0 are x=3,x=-5

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2 (x - 3) (x + 5) = 0

x = 3, x = - 5

Solution steps

2 (x - 3) (x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x + 5 = 0

Solve

x - 3 = 0 : x = 3

Solve

x + 5 = 0 : x = - 5

The solutions to the quadratic equation are:

x = 3, x = - 5

lo g_{4} (\frac{1}{32})

\frac{25 a ^{3} b ^{7}}{- 15 a ^{8} b ^{3}}

5 - 2.25

3 x^{2} - 21 x = 0

1936 - 16 t^{2} = 0

What are the solutions to the equation 2(x-3)(x+5)=0 ?
The solutions to the equation 2(x-3)(x+5)=0 are x=3,x=-5
Find the zeros of 2(x-3)(x+5)=0
The zeros of 2(x-3)(x+5)=0 are x=3,x=-5