What are the solutions to the equation (3x+10)^2=81 ?

The solutions to the equation (3x+10)^2=81 are x=-1/3 ,x=-19/3

Find the zeros of (3x+10)^2=81

The zeros of (3x+10)^2=81 are x=-1/3 ,x=-19/3

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(3 x + 10)^{2} = 81

x = - \frac{1}{3}, x = - \frac{19}{3}

Decimal Notation

x = - 0.33333 \dots, x = - 6.33333 \dots

Solution steps

(3 x + 10)^{2} = 81

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 10 = 81 : x = - \frac{1}{3}

Solve

3 x + 10 = - 81 : x = - \frac{19}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - \frac{19}{3}

lo g_{0.5} (15) = 1 - 2 x

7.5 < x

15 \cdot 15

- \frac{6}{5} k = 12

2 x^{2} - 3 x + 2 = 0

What are the solutions to the equation (3x+10)^2=81 ?
The solutions to the equation (3x+10)^2=81 are x=-1/3 ,x=-19/3
Find the zeros of (3x+10)^2=81
The zeros of (3x+10)^2=81 are x=-1/3 ,x=-19/3