What are the solutions to the equation (x^2)/2+7/2 x=2 ?

The solutions to the equation (x^2)/2+7/2 x=2 are x=(-7+sqrt(65))/2 ,x=(-7-sqrt(65))/2

Find the zeros of (x^2)/2+7/2 x=2

The zeros of (x^2)/2+7/2 x=2 are x=(-7+sqrt(65))/2 ,x=(-7-sqrt(65))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{x ^{2}}{2} + \frac{7}{2} x = 2

x = \frac{- 7 + 65}{2}, x = \frac{- 7 - 65}{2}

Decimal Notation

x = 0.53112 \dots, x = - 7.53112 \dots

Solution steps

\frac{x ^{2}}{2} + \frac{7}{2} x = 2

Multiply both sides by

2

x^{2} + 7 x = 4

Move

4

to the left side

x^{2} + 7 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 4) = 65

x_{1, 2} = \frac{- 7 \pm 65}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 65}{2 \cdot 1}, x_{2} = \frac{- 7 - 65}{2 \cdot 1}

x = \frac{- 7 + 65}{2 \cdot 1} : \frac{- 7 + 65}{2}

x = \frac{- 7 - 65}{2 \cdot 1} : \frac{- 7 - 65}{2}

The solutions to the quadratic equation are:

x = \frac{- 7 + 65}{2}, x = \frac{- 7 - 65}{2}

\frac{0.6}{6.58 \cdot 1 0 ^{22}}

x^{2} - 6 x = - 13

x^{2} - \frac{1}{5} x + \frac{1}{y}

- 2 (- 5 n + 6) + 5 (2 - 7 n)

(- \frac{2 x ^{\frac{1}{6}}}{3 y ^{4}})^{- 3}

What are the solutions to the equation (x^2)/2+7/2 x=2 ?
The solutions to the equation (x^2)/2+7/2 x=2 are x=(-7+sqrt(65))/2 ,x=(-7-sqrt(65))/2
Find the zeros of (x^2)/2+7/2 x=2
The zeros of (x^2)/2+7/2 x=2 are x=(-7+sqrt(65))/2 ,x=(-7-sqrt(65))/2