What is the answer to 8c-7-(3c-11)=5(3c+11)+6c ?

The answer to 8c-7-(3c-11)=5(3c+11)+6c is c=-51/16

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8c-7-(3c-11)=5(3c+11)+6c

8 c - 7 - (3 c - 11) = 5 (3 c + 11) + 6 c

c = - \frac{51}{16}

Solution steps

8 c - 7 - (3 c - 11) = 5 (3 c + 11) + 6 c

Expand

8 c - 7 - (3 c - 11) : 5 c + 4

Expand

5 (3 c + 11) + 6 c : 21 c + 55

5 c + 4 = 21 c + 55

Move

4

to the right side

5 c = 21 c + 51

Move

21 c

to the left side

- 16 c = 51

Divide both sides by

- 16

c = - \frac{51}{16}

f (x) = x^{2} - 3 x^{2}

27 m^{12} - 64 n^{9}

\frac{1}{2} x + 3 = 2

710 \cdot (0.6 - x) (0.06 - x) - x = 0

x^{2} + 10 x + 100

What is the answer to 8c-7-(3c-11)=5(3c+11)+6c ?
The answer to 8c-7-(3c-11)=5(3c+11)+6c is c=-51/16
Solve for c: 8c-7-(3c-11)=5(3c+11)+6c
The solution is c=-51/16