What is (4x^4y)^2*2x^3y^4 ?

The solution to (4x^4y)^2*2x^3y^4 is 32x^{11}y^6

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simplify (4x^4y)^2*2x^3y^4

simplify

(4 x^{4} y)^{2} \cdot 2 x^{3} y^{4}

32 x^{11} y^{6}

Solution steps

(4 x^{4} y)^{2} \cdot 2 x^{3} y^{4}

Simplify

(4 x^{4} y)^{2} : 16 x^{8} y^{2}

= 16 x^{8} y^{2} \cdot 2 x^{3} y^{4}

Multiply the numbers:

16 \cdot 2 = 32

= 32 x^{8} y^{2} x^{3} y^{4}

Simplify

x^{8} x^{3} : x^{11}

= 32 x^{11} y^{2} y^{4}

Simplify

y^{2} y^{4} : y^{6}

= 32 x^{11} y^{6}

a^{2} + 3 a + 2

3 x^{2} - 15 x + 18

y, x^{2} + y^{2} - 2 x - 6 y + 10 = 0

- 7 (x - 4) = - 11 (x + 8)

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