What are the solutions to the equation 3x^2+2x-9=0 ?

The solutions to the equation 3x^2+2x-9=0 are x=(-1+2sqrt(7))/3 ,x=-(1+2sqrt(7))/3

Find the zeros of 3x^2+2x-9=0

The zeros of 3x^2+2x-9=0 are x=(-1+2sqrt(7))/3 ,x=-(1+2sqrt(7))/3

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3 x^{2} + 2 x - 9 = 0

x = \frac{- 1 + 2 7}{3}, x = - \frac{1 + 2 7}{3}

Decimal Notation

x = 1.43050 \dots, x = - 2.09716 \dots

Solution steps

3 x^{2} + 2 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 9) = 47

x_{1, 2} = \frac{- 2 \pm 4 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 4 7}{2 \cdot 3}, x_{2} = \frac{- 2 - 4 7}{2 \cdot 3}

x = \frac{- 2 + 4 7}{2 \cdot 3} : \frac{- 1 + 2 7}{3}

x = \frac{- 2 - 4 7}{2 \cdot 3} : - \frac{1 + 2 7}{3}

The solutions to the quadratic equation are:

x = \frac{- 1 + 2 7}{3}, x = - \frac{1 + 2 7}{3}

\frac{2 x ^{2} - x - 1}{x ^{2} - 9} \cdot \frac{x + 3}{2 x + 1}

(x + 3) (x - 5) \leq 0

\frac{( - 2 ) ^{2} - 2 ( - 2 )}{( - 2 ) ^{2} - ( - 2 ) - 2}

5 t^{2} + 12 t - 9

9 y - 7 y - 9 = 28.64

What are the solutions to the equation 3x^2+2x-9=0 ?
The solutions to the equation 3x^2+2x-9=0 are x=(-1+2sqrt(7))/3 ,x=-(1+2sqrt(7))/3
Find the zeros of 3x^2+2x-9=0
The zeros of 3x^2+2x-9=0 are x=(-1+2sqrt(7))/3 ,x=-(1+2sqrt(7))/3