What is factor t^2+4t-5 ?

The solution to factor t^2+4t-5 is (t-1)(t+5)

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factor t^2+4t-5

factor

t^{2} + 4 t - 5

(t - 1) (t + 5)

Solution steps

t^{2} + 4 t - 5

Break the expression into groups

= (t^{2} - t) + (5 t - 5)

Factor out

t

from

t^{2} - t : t (t - 1)

Factor out

5

from

5 t - 5 : 5 (t - 1)

= t (t - 1) + 5 (t - 1)

Factor out common term

t - 1

= (t - 1) (t + 5)

2 x^{2} + 3 x - 11 = 0

3 + x < 7

- 2 (z + 11) = 6

∣ 2 x - 2 ∣ < - 8

lo g_{2} (15) + lo g_{2} (4) - lo g_{2} (6)