What are the solutions to the equation x^2-20x+72=-3x ?

The solutions to the equation x^2-20x+72=-3x are x=9,x=8

Find the zeros of x^2-20x+72=-3x

The zeros of x^2-20x+72=-3x are x=9,x=8

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x^{2} - 20 x + 72 = - 3 x

x = 9, x = 8

Solution steps

x^{2} - 20 x + 72 = - 3 x

Move

3 x

to the left side

x^{2} - 17 x + 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 1 \cdot 72}{2 \cdot 1}

(- 17)^{2} - 4 \cdot 1 \cdot 72 = 1

x_{1, 2} = \frac{- ( - 17 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 17 ) - 1}{2 \cdot 1}

x = \frac{- ( - 17 ) + 1}{2 \cdot 1} : 9

x = \frac{- ( - 17 ) - 1}{2 \cdot 1} : 8

The solutions to the quadratic equation are:

x = 9, x = 8

4 (- 1)^{4} - 24 (- 1)^{3} + 14 (- 1)^{2} - 50 (- 1) - 70

m^{2} - 5 m + 6

\frac{6 x + 3}{4 x - 2} < 12

\frac{9}{25}

\frac{k}{2} + \frac{1}{2} = 3

What are the solutions to the equation x^2-20x+72=-3x ?
The solutions to the equation x^2-20x+72=-3x are x=9,x=8
Find the zeros of x^2-20x+72=-3x
The zeros of x^2-20x+72=-3x are x=9,x=8