What are the solutions to the equation -x^2-2x=0 ?

The solutions to the equation -x^2-2x=0 are x=-2,x=0

Find the zeros of -x^2-2x=0

The zeros of -x^2-2x=0 are x=-2,x=0

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- x^{2} - 2 x = 0

x = - 2, x = 0

Solution steps

- x^{2} - 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

(- 2)^{2} - 4 (- 1) \cdot 0 = 2

x_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2}{2 ( - 1 )}, x_{2} = \frac{- ( - 2 ) - 2}{2 ( - 1 )}

x = \frac{- ( - 2 ) + 2}{2 ( - 1 )} : - 2

x = \frac{- ( - 2 ) - 2}{2 ( - 1 )} : 0

The solutions to the quadratic equation are:

x = - 2, x = 0

503.1 = 1 0^{- 8} \cdot 1118 \cdot 5 \cdot x^{2}

3 + 40 t - 16 t^{2} = 16

(x^{\frac{1}{3}})^{4}

∣ x - 5 ∣ < ∣ x + 1 ∣

\frac{1}{3 2 ^{\frac{1}{5}}}

What are the solutions to the equation -x^2-2x=0 ?
The solutions to the equation -x^2-2x=0 are x=-2,x=0
Find the zeros of -x^2-2x=0
The zeros of -x^2-2x=0 are x=-2,x=0