What is (2 2/5-6 1/2+1 1/10)^{-3} ?

The solution to (2 2/5-6 1/2+1 1/10)^{-3} is -1/27

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simplify (2 2/5-6 1/2+1 1/10)^{-3}

simplify

(2 \frac{2}{5} - 6 \frac{1}{2} + 1 \frac{1}{10})^{- 3}

- \frac{1}{27}

Solution steps

(2 \frac{2}{5} - 6 \frac{1}{2} + 1 \frac{1}{10})^{- 3}

Convert mixed numbers to improper fractions:

2 \frac{2}{5} = \frac{12}{5}

= (\frac{12}{5} - 6 \frac{1}{2} + 1 \frac{1}{10})^{- 3}

Convert mixed numbers to improper fractions:

6 \frac{1}{2} = \frac{13}{2}

= (\frac{12}{5} - \frac{13}{2} + 1 \frac{1}{10})^{- 3}

Convert mixed numbers to improper fractions:

1 \frac{1}{10} = \frac{11}{10}

= (\frac{12}{5} - \frac{13}{2} + \frac{11}{10})^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{12}{5} - \frac{13}{2} + \frac{11}{10})^{- 3} = \frac{1}{( \frac{12}{5} - \frac{13}{2} + \frac{11}{10} ) ^{3}}

= \frac{1}{( \frac{12}{5} - \frac{13}{2} + \frac{11}{10} ) ^{3}}

(\frac{12}{5} - \frac{13}{2} + \frac{11}{10})^{3} = - 27

= \frac{1}{- 27}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{1}{27}

5 x - 8 = 12

- \frac{5}{3 ^{2}}

169

3 x - 5 < 1 + x < 2 x - 3

(3 - 2) + \frac{1}{3 - 2}

What is (2 2/5-6 1/2+1 1/10)^{-3} ?
The solution to (2 2/5-6 1/2+1 1/10)^{-3} is -1/27