What is the answer to -3q+2(1-q)=-1q+0(1-q) ?

The answer to -3q+2(1-q)=-1q+0(1-q) is q= 1/2

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-3q+2(1-q)=-1q+0(1-q)

- 3 q + 2 (1 - q) = - 1 q + 0 (1 - q)

q = \frac{1}{2}

Decimal Notation

q = 0.5

Solution steps

- 3 q + 2 (1 - q) = - 1 \cdot q + 0 \cdot (1 - q)

Multiply:

1 \cdot q = q

- 3 q + 2 (1 - q) = - q + 0 \cdot (- q + 1)

Apply rule

0 \cdot a = 0

- 3 q + 2 (1 - q) = - q + 0

- q + 0 = - q

- 3 q + 2 (1 - q) = - q

Expand

- 3 q + 2 (1 - q) : - 5 q + 2

- 5 q + 2 = - q

Move

2

to the right side

- 5 q = - q - 2

Move

q

to the left side

- 4 q = - 2

Divide both sides by

- 4

q = \frac{1}{2}

3 x^{2} + 10 x \geq - 2 x - 9

\frac{- 2 - 5 i}{3}

16 x^{2} + 40 x + 25

x^{2} + 8 x + 16 = - 9

\frac{3 - 2 x}{5} \leq \frac{5 x - 1}{2}

What is the answer to -3q+2(1-q)=-1q+0(1-q) ?
The answer to -3q+2(1-q)=-1q+0(1-q) is q= 1/2
Solve for q: -3q+2(1-q)=-1q+0(1-q)
The solution is q= 1/2