What are the solutions to the equation 15x=25x^2+2 ?

The solutions to the equation 15x=25x^2+2 are x= 2/5 ,x= 1/5

Find the zeros of 15x=25x^2+2

The zeros of 15x=25x^2+2 are x= 2/5 ,x= 1/5

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15 x = 25 x^{2} + 2

x = \frac{2}{5}, x = \frac{1}{5}

Decimal Notation

x = 0.4, x = 0.2

Solution steps

15 x = 25 x^{2} + 2

Switch sides

25 x^{2} + 2 = 15 x

Move

15 x

to the left side

25 x^{2} + 2 - 15 x = 0

Write in the standard form

a x^{2} + b x + c = 0

25 x^{2} - 15 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 25 \cdot 2}{2 \cdot 25}

(- 15)^{2} - 4 \cdot 25 \cdot 2 = 5

x_{1, 2} = \frac{- ( - 15 ) \pm 5}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 5}{2 \cdot 25}, x_{2} = \frac{- ( - 15 ) - 5}{2 \cdot 25}

x = \frac{- ( - 15 ) + 5}{2 \cdot 25} : \frac{2}{5}

x = \frac{- ( - 15 ) - 5}{2 \cdot 25} : \frac{1}{5}

The solutions to the quadratic equation are:

x = \frac{2}{5}, x = \frac{1}{5}

88 = 151 t - 16 t^{2}

\frac{5}{7} n = - \frac{5}{16}

2 0^{- \frac{1}{2}}

2 q^{4} + 9 q^{3} - 18 q^{2}

v^{2} - 15 v + 36

What are the solutions to the equation 15x=25x^2+2 ?
The solutions to the equation 15x=25x^2+2 are x= 2/5 ,x= 1/5
Find the zeros of 15x=25x^2+2
The zeros of 15x=25x^2+2 are x= 2/5 ,x= 1/5