What are the solutions to the equation 4a^2-3a=0 ?

The solutions to the equation 4a^2-3a=0 are a= 3/4 ,a=0

Find the zeros of 4a^2-3a=0

The zeros of 4a^2-3a=0 are a= 3/4 ,a=0

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4 a^{2} - 3 a = 0

a = \frac{3}{4}, a = 0

Decimal Notation

a = 0.75, a = 0

Solution steps

4 a^{2} - 3 a = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 3)^{2} - 4 \cdot 4 \cdot 0 = 3

a_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 4}

Separate the solutions

a_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 4}, a_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 4}

a = \frac{- ( - 3 ) + 3}{2 \cdot 4} : \frac{3}{4}

a = \frac{- ( - 3 ) - 3}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

a = \frac{3}{4}, a = 0

2 x + \frac{x}{4} = x + 5

\frac{4}{5} + \frac{2}{7}

(x - 1) (x + 8) = 0

(\frac{n}{3} - \frac{3}{n})^{2}

- 7 x^{4} y^{2} + 14 x y^{3} + 21 x y^{4}

What are the solutions to the equation 4a^2-3a=0 ?
The solutions to the equation 4a^2-3a=0 are a= 3/4 ,a=0
Find the zeros of 4a^2-3a=0
The zeros of 4a^2-3a=0 are a= 3/4 ,a=0