What is f(1)((x^2-2))/(x^2+x+1) ?

The solution to f(1)((x^2-2))/(x^2+x+1) is (f(x^2-2))/(x^2+x+1)

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simplify f(1)((x^2-2))/(x^2+x+1)

simplify

f (1) \frac{( x ^{2} - 2 )}{x ^{2} + x + 1}

\frac{f ( x ^{2} - 2 )}{x ^{2} + x + 1}

Solution steps

f (1) \frac{x ^{2} - 2}{x ^{2} + x + 1}

Apply rule:

(a) = a

(1) = 1

= f \cdot 1 \cdot \frac{x ^{2} - 2}{x ^{2} + x + 1}

Apply rule:

a \cdot 1 = a

= f \frac{x ^{2} - 2}{x ^{2} + x + 1}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{f ( x ^{2} - 2 )}{x ^{2} + x + 1}

(x + 2) (x - 4) + 7 (x - 4)

- 2.17 = 0.35 r

∣ 3 + 4 i ∣

x = 0.5 \cdot (1 - \frac{0.46}{2}) \cdot (1 - 0.46)^{2 - 2}

\frac{4}{5} - \frac{2}{5}

What is f(1)((x^2-2))/(x^2+x+1) ?
The solution to f(1)((x^2-2))/(x^2+x+1) is (f(x^2-2))/(x^2+x+1)