What are the solutions to the equation 21^2+b^2=35^2 ?

The solutions to the equation 21^2+b^2=35^2 are b=28,b=-28

Find the zeros of 21^2+b^2=35^2

The zeros of 21^2+b^2=35^2 are b=28,b=-28

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2 1^{2} + b^{2} = 3 5^{2}

b = 28, b = - 28

Solution steps

2 1^{2} + b^{2} = 3 5^{2}

Move

2 1^{2}

to the right side

b^{2} = 784

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 784, b = - 784

784 = 28

- 784 = - 28

b = 28, b = - 28

- \frac{4}{5} + 4

\frac{90}{360} \cdot 16 π

14252 (0.5)^{\frac{40}{32}}

u^{2} + 5 u + 4

\frac{2}{3} = \frac{c}{18}

What are the solutions to the equation 21^2+b^2=35^2 ?
The solutions to the equation 21^2+b^2=35^2 are b=28,b=-28
Find the zeros of 21^2+b^2=35^2
The zeros of 21^2+b^2=35^2 are b=28,b=-28