What are the solutions to the equation x^2+45x=-200 ?

The solutions to the equation x^2+45x=-200 are x=-5,x=-40

Find the zeros of x^2+45x=-200

The zeros of x^2+45x=-200 are x=-5,x=-40

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x^{2} + 45 x = - 200

x = - 5, x = - 40

Solution steps

x^{2} + 45 x = - 200

Move

200

to the left side

x^{2} + 45 x + 200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 45 \pm 4 5 ^{2} - 4 \cdot 1 \cdot 200}{2 \cdot 1}

4 5^{2} - 4 \cdot 1 \cdot 200 = 35

x_{1, 2} = \frac{- 45 \pm 35}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 45 + 35}{2 \cdot 1}, x_{2} = \frac{- 45 - 35}{2 \cdot 1}

x = \frac{- 45 + 35}{2 \cdot 1} : - 5

x = \frac{- 45 - 35}{2 \cdot 1} : - 40

The solutions to the quadratic equation are:

x = - 5, x = - 40

- \frac{x}{11} - 2 + 5 > 9

∣ 8 s - 2 ∣ \geq 0

2 y^{2} = 40

x^{2} - 3 = 13

2 π - \frac{5 π}{3}

What are the solutions to the equation x^2+45x=-200 ?
The solutions to the equation x^2+45x=-200 are x=-5,x=-40
Find the zeros of x^2+45x=-200
The zeros of x^2+45x=-200 are x=-5,x=-40