What are the solutions to the equation solvefor y,x^2+4y^2=0 ?

The solutions to the equation solvefor y,x^2+4y^2=0 are y=(ix)/2 ,y=-(ix)/2

Find the zeros of solvefor y,x^2+4y^2=0

The zeros of solvefor y,x^2+4y^2=0 are y=(ix)/2 ,y=-(ix)/2

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solve for

y, x^{2} + 4 y^{2} = 0

y = \frac{i x}{2}, y = - \frac{i x}{2}

Solution steps

x^{2} + 4 y^{2} = 0

Move

x^{2}

to the right side

4 y^{2} = - x^{2}

Divide both sides by

4

y^{2} = - \frac{x ^{2}}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - \frac{x ^{2}}{4}, y = - - \frac{x ^{2}}{4}

Simplify

- \frac{x ^{2}}{4} : \frac{i x}{2}

Simplify

- - \frac{x ^{2}}{4} : - \frac{i x}{2}

y = \frac{i x}{2}, y = - \frac{i x}{2}

\frac{u}{5} = \frac{u}{3} - 4

(e^{- t})^{2}

9 n + 12 = 15 n - 6

(4 x^{2} + 7 x^{3} y^{2}) - (- 6 x^{2} - 7 x^{3} y^{2} - 4 x) - (10 x + 9 x^{2})

5 t^{2} = 26 t + 24

What are the solutions to the equation solvefor y,x^2+4y^2=0 ?
The solutions to the equation solvefor y,x^2+4y^2=0 are y=(ix)/2 ,y=-(ix)/2
Find the zeros of solvefor y,x^2+4y^2=0
The zeros of solvefor y,x^2+4y^2=0 are y=(ix)/2 ,y=-(ix)/2