What are the solutions to the equation (x-2)(x+8)=0 ?

The solutions to the equation (x-2)(x+8)=0 are x=2,x=-8

Find the zeros of (x-2)(x+8)=0

The zeros of (x-2)(x+8)=0 are x=2,x=-8

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(x - 2) (x + 8) = 0

x = 2, x = - 8

Solution steps

(x - 2) (x + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 8 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 8 = 0 : x = - 8

The solutions to the quadratic equation are:

x = 2, x = - 8

- \frac{1}{3} \cdot 12

4 n^{2} - 28 n + 49

ln (53) = x

- c + 1.52 = 8.25

16 x^{2} - 25 y^{2}

What are the solutions to the equation (x-2)(x+8)=0 ?
The solutions to the equation (x-2)(x+8)=0 are x=2,x=-8
Find the zeros of (x-2)(x+8)=0
The zeros of (x-2)(x+8)=0 are x=2,x=-8