What are the solutions to the equation 0=3(x-5)^2-12 ?

The solutions to the equation 0=3(x-5)^2-12 are x=7,x=3

Find the zeros of 0=3(x-5)^2-12

The zeros of 0=3(x-5)^2-12 are x=7,x=3

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0 = 3 (x - 5)^{2} - 12

x = 7, x = 3

Solution steps

0 = 3 (x - 5)^{2} - 12

Switch sides

3 (x - 5)^{2} - 12 = 0

Move

12

to the right side

3 (x - 5)^{2} = 12

Divide both sides by

3

(x - 5)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = 4 : x = 7

Solve

x - 5 = - 4 : x = 3

The solutions to the quadratic equation are:

x = 7, x = 3

- (\frac{4}{x + 6}) > - (\frac{5}{x + 7})

4 (x + 2) - 4 > - 2 (x - 4) + 14

125 - 27 u^{3}

∣ 3 x - 7 ∣ \leq 8

3 x^{2} - 16 x - 12

What are the solutions to the equation 0=3(x-5)^2-12 ?
The solutions to the equation 0=3(x-5)^2-12 are x=7,x=3
Find the zeros of 0=3(x-5)^2-12
The zeros of 0=3(x-5)^2-12 are x=7,x=3