What are the solutions to the equation x^2-8x+15=0 ?

The solutions to the equation x^2-8x+15=0 are x=5,x=3

Find the zeros of x^2-8x+15=0

The zeros of x^2-8x+15=0 are x=5,x=3

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x^{2} - 8 x + 15 = 0

x = 5, x = 3

Solution steps

x^{2} - 8 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 15 = 2

x_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2}{2 \cdot 1} : 5

x = \frac{- ( - 8 ) - 2}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 5, x = 3

4 (x - 3) - 2 (x - 1) > 0

∣ 8 x - 5 ∣ \leq 8

6 (j + 3) > - 6

15 x - 10 = 6 x - (x + 2) + (- x + 3)

f = 5^{- 1}

What are the solutions to the equation x^2-8x+15=0 ?
The solutions to the equation x^2-8x+15=0 are x=5,x=3
Find the zeros of x^2-8x+15=0
The zeros of x^2-8x+15=0 are x=5,x=3