What is (4-a)/(5a)*(a^2+5a)/(a^2+a-20) ?

The solution to (4-a)/(5a)*(a^2+5a)/(a^2+a-20) is -1/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (4-a)/(5a)*(a^2+5a)/(a^2+a-20)

simplify

\frac{4 - a}{5 a} \cdot \frac{a ^{2} + 5 a}{a ^{2} + a - 20}

- \frac{1}{5}

Decimal Notation

- 0.2

Solution steps

\frac{4 - a}{5 a} \cdot \frac{a ^{2} + 5 a}{a ^{2} + a - 20}

Cancel

\frac{a ^{2} + 5 a}{a ^{2} + a - 20} : \frac{a}{a - 4}

= \frac{4 - a}{5 a} \cdot \frac{a}{a - 4}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( 4 - a ) a}{5 a ( a - 4 )}

Cancel the common factor:

a

= \frac{4 - a}{5 ( a - 4 )}

4 - a = - (a - 4)

= \frac{- ( a - 4 )}{5 ( a - 4 )}

Cancel the common factor:

a - 4

= \frac{- 1}{5}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{1}{5}

2 n^{2} - n - 4 = 2

\frac{3}{7} = \frac{9}{28}

1.49 m \leq 8.94

lo g_{3} (x) = 4

3 x^{\frac{3}{2}} - 9 x^{\frac{1}{2}} - 6 x^{- \frac{1}{2}}

What is (4-a)/(5a)*(a^2+5a)/(a^2+a-20) ?
The solution to (4-a)/(5a)*(a^2+5a)/(a^2+a-20) is -1/5