What is the answer to ((sqrt(3))/7)^2+(x/7)=1 ?

The answer to ((sqrt(3))/7)^2+(x/7)=1 is x= 46/7

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((sqrt(3))/7)^2+(x/7)=1

(\frac{3}{7})^{2} + (\frac{x}{7}) = 1

x = \frac{46}{7}

Decimal Notation

x = 6.57142 \dots

Solution steps

(\frac{3}{7})^{2} + (\frac{x}{7}) = 1

Simplify

(\frac{3}{7})^{2} + (\frac{x}{7}) : \frac{3}{49} + \frac{x}{7}

\frac{3}{49} + \frac{x}{7} = 1

Move

\frac{3}{49}

to the right side

\frac{x}{7} = \frac{46}{49}

Multiply both sides by

7

x = \frac{46}{7}

12 x - 9 = 8 x - 37

- 9 x + 3 < 57 + 18 x

6 w + 2 = 9 w + 14

4 - 7 z = 6 - 2 z

(3 x)^{\frac{2}{3}}

What is the answer to ((sqrt(3))/7)^2+(x/7)=1 ?
The answer to ((sqrt(3))/7)^2+(x/7)=1 is x= 46/7
Solve for x: ((sqrt(3))/7)^2+(x/7)=1
The solution is x= 46/7