What are the solutions to the equation a^2+a+a^2=1 ?

The solutions to the equation a^2+a+a^2=1 are a= 1/2 ,a=-1

Find the zeros of a^2+a+a^2=1

The zeros of a^2+a+a^2=1 are a= 1/2 ,a=-1

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a^{2} + a + a^{2} = 1

a = \frac{1}{2}, a = - 1

Decimal Notation

a = 0.5, a = - 1

Solution steps

a^{2} + a + a^{2} = 1

Refine

2 a^{2} + a = 1

Move

1

to the left side

2 a^{2} + a - 1 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 1) = 3

a_{1, 2} = \frac{- 1 \pm 3}{2 \cdot 2}

Separate the solutions

a_{1} = \frac{- 1 + 3}{2 \cdot 2}, a_{2} = \frac{- 1 - 3}{2 \cdot 2}

a = \frac{- 1 + 3}{2 \cdot 2} : \frac{1}{2}

a = \frac{- 1 - 3}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

a = \frac{1}{2}, a = - 1

2 x^{2} - 72

18 n = 522

3 (x - 4) > 15

180 - 5 \cdot 2^{2}

\frac{3 x + 3}{9} = \frac{2 x + 2}{6}

What are the solutions to the equation a^2+a+a^2=1 ?
The solutions to the equation a^2+a+a^2=1 are a= 1/2 ,a=-1
Find the zeros of a^2+a+a^2=1
The zeros of a^2+a+a^2=1 are a= 1/2 ,a=-1