What are the solutions to the equation 2x^2+8x+2=0 ?

The solutions to the equation 2x^2+8x+2=0 are x=-2+sqrt(3),x=-2-sqrt(3)

Find the zeros of 2x^2+8x+2=0

The zeros of 2x^2+8x+2=0 are x=-2+sqrt(3),x=-2-sqrt(3)

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2 x^{2} + 8 x + 2 = 0

x = - 2 + 3, x = - 2 - 3

Decimal Notation

x = - 0.26794 \dots, x = - 3.73205 \dots

Solution steps

2 x^{2} + 8 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

8^{2} - 4 \cdot 2 \cdot 2 = 43

x_{1, 2} = \frac{- 8 \pm 4 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 4 3}{2 \cdot 2}, x_{2} = \frac{- 8 - 4 3}{2 \cdot 2}

x = \frac{- 8 + 4 3}{2 \cdot 2} : - 2 + 3

x = \frac{- 8 - 4 3}{2 \cdot 2} : - 2 - 3

The solutions to the quadratic equation are:

x = - 2 + 3, x = - 2 - 3

- 12 v - 9 + 7 v = 26

6 (x - 1) > 18

7 x - 3 = - 10

3 + 5 x \geq 18

\frac{x - 3}{2 x + 5} \geq 1

What are the solutions to the equation 2x^2+8x+2=0 ?
The solutions to the equation 2x^2+8x+2=0 are x=-2+sqrt(3),x=-2-sqrt(3)
Find the zeros of 2x^2+8x+2=0
The zeros of 2x^2+8x+2=0 are x=-2+sqrt(3),x=-2-sqrt(3)