What are the solutions to the equation 7^2-b^2=10 ?

The solutions to the equation 7^2-b^2=10 are b=sqrt(39),b=-sqrt(39)

Find the zeros of 7^2-b^2=10

The zeros of 7^2-b^2=10 are b=sqrt(39),b=-sqrt(39)

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7^{2} - b^{2} = 10

b = 39, b = - 39

Decimal Notation

b = 6.24499 \dots, b = - 6.24499 \dots

Solution steps

7^{2} - b^{2} = 10

Move

7^{2}

to the right side

- b^{2} = - 39

Divide both sides by

- 1

b^{2} = 39

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 39, b = - 39

∣ 1 + 4 x ∣ = 3 x

1 < 3 x + 7 \leq 11

y^{2} - 12 y = - 19

11

\frac{3 x - 1}{x + 2} \geq 1

What are the solutions to the equation 7^2-b^2=10 ?
The solutions to the equation 7^2-b^2=10 are b=sqrt(39),b=-sqrt(39)
Find the zeros of 7^2-b^2=10
The zeros of 7^2-b^2=10 are b=sqrt(39),b=-sqrt(39)