What are the solutions to the equation v^2-5v=0 ?

The solutions to the equation v^2-5v=0 are v=5,v=0

Find the zeros of v^2-5v=0

The zeros of v^2-5v=0 are v=5,v=0

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v^{2} - 5 v = 0

v = 5, v = 0

Solution steps

v^{2} - 5 v = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 0 = 5

v_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 1}, v_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 1}

v = \frac{- ( - 5 ) + 5}{2 \cdot 1} : 5

v = \frac{- ( - 5 ) - 5}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

v = 5, v = 0

3 x^{2} + 8 x - 11

(\frac{1}{8})^{0}

- 12 n^{2} - 11 n + 15

5 x - (x - 8) > 9 + 3 (2 x - 3)

z^{2} - (3 - 2 i) z + 1 - 3 i = 0

What are the solutions to the equation v^2-5v=0 ?
The solutions to the equation v^2-5v=0 are v=5,v=0
Find the zeros of v^2-5v=0
The zeros of v^2-5v=0 are v=5,v=0