What are the solutions to the equation 42-4(x-10)^2=46 ?

The solutions to the equation 42-4(x-10)^2=46 are x=i+10,x=-i+10

Find the zeros of 42-4(x-10)^2=46

The zeros of 42-4(x-10)^2=46 are x=i+10,x=-i+10

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42 - 4 (x - 10)^{2} = 46

x = i + 10, x = - i + 10

Solution steps

42 - 4 (x - 10)^{2} = 46

Move

42

to the right side

- 4 (x - 10)^{2} = 4

Divide both sides by

- 4

(x - 10)^{2} = - 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 10 = - 1 : x = i + 10

Solve

x - 10 = - - 1 : x = - i + 10

The solutions to the quadratic equation are:

x = i + 10, x = - i + 10

316

2 x - 10 = 44 + 8 x

\frac{48}{75}

27 x + 18

\frac{4}{a - 2} - \frac{5}{a}

What are the solutions to the equation 42-4(x-10)^2=46 ?
The solutions to the equation 42-4(x-10)^2=46 are x=i+10,x=-i+10
Find the zeros of 42-4(x-10)^2=46
The zeros of 42-4(x-10)^2=46 are x=i+10,x=-i+10