What are the solutions to the equation 4x^2-5x-24=0 ?

The solutions to the equation 4x^2-5x-24=0 are x=(5+sqrt(409))/8 ,x=(5-sqrt(409))/8

Find the zeros of 4x^2-5x-24=0

The zeros of 4x^2-5x-24=0 are x=(5+sqrt(409))/8 ,x=(5-sqrt(409))/8

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4 x^{2} - 5 x - 24 = 0

x = \frac{5 + 409}{8}, x = \frac{5 - 409}{8}

Decimal Notation

x = 3.15296 \dots, x = - 1.90296 \dots

Solution steps

4 x^{2} - 5 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 4 ( - 24 )}{2 \cdot 4}

(- 5)^{2} - 4 \cdot 4 (- 24) = 409

x_{1, 2} = \frac{- ( - 5 ) \pm 409}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 409}{2 \cdot 4}, x_{2} = \frac{- ( - 5 ) - 409}{2 \cdot 4}

x = \frac{- ( - 5 ) + 409}{2 \cdot 4} : \frac{5 + 409}{8}

x = \frac{- ( - 5 ) - 409}{2 \cdot 4} : \frac{5 - 409}{8}

The solutions to the quadratic equation are:

x = \frac{5 + 409}{8}, x = \frac{5 - 409}{8}

∣ x - 2 ∣ + ∣ x - 5 ∣ \leq 5

lo g_{64} (2)

2 x^{3} - 4 x^{2} - 10 x + 20

\frac{11}{12} x - \frac{1}{4} = 8

5 x^{2} - 22 x + 7 = - 1

What are the solutions to the equation 4x^2-5x-24=0 ?
The solutions to the equation 4x^2-5x-24=0 are x=(5+sqrt(409))/8 ,x=(5-sqrt(409))/8
Find the zeros of 4x^2-5x-24=0
The zeros of 4x^2-5x-24=0 are x=(5+sqrt(409))/8 ,x=(5-sqrt(409))/8