What are the solutions to the equation -81+100x^2=0 ?

The solutions to the equation -81+100x^2=0 are x= 9/10 ,x=-9/10

Find the zeros of -81+100x^2=0

The zeros of -81+100x^2=0 are x= 9/10 ,x=-9/10

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- 81 + 100 x^{2} = 0

x = \frac{9}{10}, x = - \frac{9}{10}

Decimal Notation

x = 0.9, x = - 0.9

Solution steps

- 81 + 100 x^{2} = 0

Move

81

to the right side

100 x^{2} = 81

Divide both sides by

100

x^{2} = \frac{81}{100}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{81}{100}, x = - \frac{81}{100}

\frac{81}{100} = \frac{9}{10}

- \frac{81}{100} = - \frac{9}{10}

x = \frac{9}{10}, x = - \frac{9}{10}

f (y) = \frac{4 y - 5}{2} - \frac{2 y - 1}{6}

∣ 4 x + 5 ∣ < 7

5 - 16 + 3 - 81

432 c^{3} d^{2}

3 m^{2} - 8 m - 3

What are the solutions to the equation -81+100x^2=0 ?
The solutions to the equation -81+100x^2=0 are x= 9/10 ,x=-9/10
Find the zeros of -81+100x^2=0
The zeros of -81+100x^2=0 are x= 9/10 ,x=-9/10