What are the solutions to the equation 6y^2+5=-17y ?

The solutions to the equation 6y^2+5=-17y are y=-1/3 ,y=-5/2

Find the zeros of 6y^2+5=-17y

The zeros of 6y^2+5=-17y are y=-1/3 ,y=-5/2

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6 y^{2} + 5 = - 17 y

y = - \frac{1}{3}, y = - \frac{5}{2}

Decimal Notation

y = - 0.33333 \dots, y = - 2.5

Solution steps

6 y^{2} + 5 = - 17 y

Move

17 y

to the left side

6 y^{2} + 5 + 17 y = 0

Write in the standard form

a x^{2} + b x + c = 0

6 y^{2} + 17 y + 5 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 6 \cdot 5}{2 \cdot 6}

1 7^{2} - 4 \cdot 6 \cdot 5 = 13

y_{1, 2} = \frac{- 17 \pm 13}{2 \cdot 6}

Separate the solutions

y_{1} = \frac{- 17 + 13}{2 \cdot 6}, y_{2} = \frac{- 17 - 13}{2 \cdot 6}

y = \frac{- 17 + 13}{2 \cdot 6} : - \frac{1}{3}

y = \frac{- 17 - 13}{2 \cdot 6} : - \frac{5}{2}

The solutions to the quadratic equation are:

y = - \frac{1}{3}, y = - \frac{5}{2}

\frac{2 + i}{5 + i}

y^{2} + 11 y + 18

3 x + 9 = 4 x

u^{4} y^{4} - 16 y^{4}

3 x^{2} = 300

What are the solutions to the equation 6y^2+5=-17y ?
The solutions to the equation 6y^2+5=-17y are y=-1/3 ,y=-5/2
Find the zeros of 6y^2+5=-17y
The zeros of 6y^2+5=-17y are y=-1/3 ,y=-5/2