What is (7/9*5/3+2/4-1/4)\div 6/9 ?

The solution to (7/9*5/3+2/4-1/4)\div 6/9 is 2 23/72

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(7/9*5/3+2/4-1/4)\div 6/9

(\frac{7}{9} \cdot \frac{5}{3} + \frac{2}{4} - \frac{1}{4}) \div \frac{6}{9}

2 \frac{23}{72}

Solution steps

(\frac{7}{9} \cdot \frac{5}{3} + \frac{2}{4} - \frac{1}{4}) \div \frac{6}{9}

\frac{2}{4} = \frac{1}{2}

= (\frac{7}{9} \cdot \frac{5}{3} + \frac{1}{2} - \frac{1}{4}) \div \frac{6}{9}

\frac{6}{9} = \frac{2}{3}

= (\frac{7}{9} \cdot \frac{5}{3} + \frac{1}{2} - \frac{1}{4}) \div \frac{2}{3}

Follow the PEMDAS order of operations

Calculate within parentheses

(\frac{7}{9} \frac{5}{3} + \frac{1}{2} - \frac{1}{4}) : \frac{167}{108}

= \frac{167}{108} \div \frac{2}{3}

Multiply and divide (left to right)

\frac{167}{108} \div \frac{2}{3} : \frac{167}{72}

= \frac{167}{72}

Convert improper fractions to mixed numbers:

\frac{167}{72} = 2 \frac{23}{72}

= 2 \frac{23}{72}

\frac{1 + i}{7 + 7 i}

3 y + 4 = 22

- \frac{8}{5} + \frac{6}{7} u = - \frac{5}{2}

lo g_{2} (80) - lo g_{2} (5)

3 x - 2 \leq 2 x + 1

What is (7/9*5/3+2/4-1/4)\div 6/9 ?
The solution to (7/9*5/3+2/4-1/4)\div 6/9 is 2 23/72