What is -x^2-10x-26<=-5 ?

The solution to -x^2-10x-26 =-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-x^2-10x-26<=-5

- x^{2} - 10 x - 26 \leq - 5

x \leq - 7 or x \geq - 3

Interval Notation

(- \infty, - 7] \cup [- 3, \infty)

Solution steps

- x^{2} - 10 x - 26 \leq - 5

Rewrite in standard form

- x^{2} - 10 x - 21 \leq 0

Factor

- x^{2} - 10 x - 21 : - (x + 3) (x + 7)

- (x + 3) (x + 7) \leq 0

Multiply both sides by

- 1

(reverse the inequality)

(- (x + 3) (x + 7)) (- 1) \geq 0 \cdot (- 1)

Simplify

(x + 3) (x + 7) \geq 0

Identify the intervals

x \leq - 7 or x \geq - 3

\frac{4 a b ^{- 2}}{- 3 c ^{- 2}}

\frac{( x + 3 ) ( x - 3 ) - 4}{2} - \frac{x - 2}{3} = \frac{( x - 2 ) ^{2} + 1}{6}

3^{2} + 6^{2} = c^{2}

\frac{x ^{3} + 8}{x ^{4} - 16}

- 8 \leq 5 x - 7 \leq 5