What are the solutions to the equation c^2-12c=-76 ?

The solutions to the equation c^2-12c=-76 are c=6+2sqrt(10)i,c=6-2sqrt(10)i

Find the zeros of c^2-12c=-76

The zeros of c^2-12c=-76 are c=6+2sqrt(10)i,c=6-2sqrt(10)i

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c^{2} - 12 c = - 76

c = 6 + 210 i, c = 6 - 210 i

Solution steps

c^{2} - 12 c = - 76

Move

76

to the left side

c^{2} - 12 c + 76 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 76}{2 \cdot 1}

Simplify

(- 12)^{2} - 4 \cdot 1 \cdot 76 : 410 i

c_{1, 2} = \frac{- ( - 12 ) \pm 4 10 i}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- ( - 12 ) + 4 10 i}{2 \cdot 1}, c_{2} = \frac{- ( - 12 ) - 4 10 i}{2 \cdot 1}

c = \frac{- ( - 12 ) + 4 10 i}{2 \cdot 1} : 6 + 210 i

c = \frac{- ( - 12 ) - 4 10 i}{2 \cdot 1} : 6 - 210 i

The solutions to the quadratic equation are:

c = 6 + 210 i, c = 6 - 210 i

8 n + 2 (- 8 n + 3) \leq n + 2 + 9 n

3 - \frac{3}{2} y = - 2

∣ x + 10 ∣ \geq 4

6 \cdot 4 + \frac{4}{2} (- 3 \cdot 7)

z^{3} + 8

What are the solutions to the equation c^2-12c=-76 ?
The solutions to the equation c^2-12c=-76 are c=6+2sqrt(10)i,c=6-2sqrt(10)i
Find the zeros of c^2-12c=-76
The zeros of c^2-12c=-76 are c=6+2sqrt(10)i,c=6-2sqrt(10)i