What are the solutions to the equation 5x^2+3x+5=0 ?

The solutions to the equation 5x^2+3x+5=0 are x=-3/10+i(sqrt(91))/(10),x=-3/10-i(sqrt(91))/(10)

Find the zeros of 5x^2+3x+5=0

The zeros of 5x^2+3x+5=0 are x=-3/10+i(sqrt(91))/(10),x=-3/10-i(sqrt(91))/(10)

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5 x^{2} + 3 x + 5 = 0

x = - \frac{3}{10} + i \frac{91}{10}, x = - \frac{3}{10} - i \frac{91}{10}

Solution steps

5 x^{2} + 3 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 5 \cdot 5}{2 \cdot 5}

Simplify

3^{2} - 4 \cdot 5 \cdot 5 : 91 i

x_{1, 2} = \frac{- 3 \pm 91 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 3 + 91 i}{2 \cdot 5}, x_{2} = \frac{- 3 - 91 i}{2 \cdot 5}

x = \frac{- 3 + 91 i}{2 \cdot 5} : - \frac{3}{10} + i \frac{91}{10}

x = \frac{- 3 - 91 i}{2 \cdot 5} : - \frac{3}{10} - i \frac{91}{10}

The solutions to the quadratic equation are:

x = - \frac{3}{10} + i \frac{91}{10}, x = - \frac{3}{10} - i \frac{91}{10}

5 x^{2} + 10 x

1 - a^{2}

s^{2} - 7 s + 12 = 0

5 x + 11 < 26

53 \cdot 23

What are the solutions to the equation 5x^2+3x+5=0 ?
The solutions to the equation 5x^2+3x+5=0 are x=-3/10+i(sqrt(91))/(10),x=-3/10-i(sqrt(91))/(10)
Find the zeros of 5x^2+3x+5=0
The zeros of 5x^2+3x+5=0 are x=-3/10+i(sqrt(91))/(10),x=-3/10-i(sqrt(91))/(10)